(1/5)(4x-1)=7

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Solution for (1/5)(4x-1)=7 equation:



(1/5)(4x-1)=7
We move all terms to the left:
(1/5)(4x-1)-(7)=0
Domain of the equation: 5)(4x-1)!=0
x∈R
We add all the numbers together, and all the variables
(+1/5)(4x-1)-7=0
We multiply parentheses ..
(+4x^2+1/5*-1)-7=0
We multiply all the terms by the denominator
(+4x^2+1-7*5*-1)=0
We get rid of parentheses
4x^2+1-1-7*5*=0
We add all the numbers together, and all the variables
4x^2=0
a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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