(1/5)(4x-1)=7

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Solution for (1/5)(4x-1)=7 equation: 



(1/5)(4x-1)=7

We move all terms to the left:

(1/5)(4x-1)-(7)=0



Domain of the equation: 5)(4x-1)!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)(4x-1)-7=0

We multiply parentheses ..

(+4x^2+1/5*-1)-7=0

We multiply all the terms by the denominator


(+4x^2+1-7*5*-1)=0

We get rid of parentheses

4x^2+1-1-7*5*=0

We add all the numbers together, and all the variables

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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