(1/5)(x)-1=2/3

Solution for (1/5)(x)-1=2/3 equation:

(1/5)(x)-1=2/3

We move all terms to the left:

(1/5)(x)-1-(2/3)=0


Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/5)x-1-(+2/3)=0

We multiply parentheses

x^2-1-(+2/3)=0

We get rid of parentheses

x^2-1-2/3=0

We multiply all the terms by the denominator


x^2*3-2-1*3=0

We add all the numbers together, and all the variables

x^2*3-5=0

Wy multiply elements

3x^2-5=0

a = 3; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·3·(-5)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{15}}{2*3}=\frac{0-2\sqrt{15}}{6}
=-\frac{2\sqrt{15}}{6}
=-\frac{\sqrt{15}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{15}}{2*3}=\frac{0+2\sqrt{15}}{6}
=\frac{2\sqrt{15}}{6}
=\frac{\sqrt{15}}{3}
$