(1/5)(x+0.5)+5.24=(3/2)x+0.7(x+2.2)

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Solution for (1/5)(x+0.5)+5.24=(3/2)x+0.7(x+2.2) equation: 



(1/5)(x+0.5)+5.24=(3/2)x+0.7(x+2.2)

We move all terms to the left:

(1/5)(x+0.5)+5.24-((3/2)x+0.7(x+2.2))=0



Domain of the equation: 5)(x+0.5)!=0

x∈R





Domain of the equation: 2)x+0.7(x+2.2))!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)(x+0.5)-((+3/2)x+0.7(x+2.2))+5.24=0

We multiply parentheses ..

(+x^2+1/5*0.5)-((+3/2)x+0.7(x+2.2))+5.24=0

We calculate fractions

We do not support expression: x^3

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