(1/5)(x+4)(x-2)(x-3)=0

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Solution for (1/5)(x+4)(x-2)(x-3)=0 equation: 



(1/5)(x+4)(x-2)(x-3)=0



Domain of the equation: 5)(x+4)(x-2)(x-3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)(x+4)(x-2)(x-3)=0

We multiply parentheses ..

(+x^2+1/5*4)(x-2)(x-3)=0

We multiply all the terms by the denominator


(+x^2+1=0

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