(1/5)+(2/3)x=x-2

Solution for (1/5)+(2/3)x=x-2 equation:

(1/5)+(2/3)x=x-2

We move all terms to the left:

(1/5)+(2/3)x-(x-2)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+2/3)x-(x-2)+(+1/5)=0

We multiply parentheses

2x^2-(x-2)+(+1/5)=0

We get rid of parentheses

2x^2-x+2+1/5=0

We multiply all the terms by the denominator


2x^2*5-x*5+1+2*5=0

We add all the numbers together, and all the variables

2x^2*5-x*5+11=0

Wy multiply elements

10x^2-5x+11=0

a = 10; b = -5; c = +11;
Δ = b2-4ac
Δ = -52-4·10·11
Δ = -415
Delta is less than zero, so there is no solution for the equation