(1/5)-(6/5x)=(4/x)

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Solution for (1/5)-(6/5x)=(4/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/5-((6/5)*x) = 4/x // - 4/x

1/5-((6/5)*x)-(4/x) = 0

(-6/5)*x-4*x^-1+1/5 = 0

1/5*x^0-6/5*x^1-4*x^-1 = 0

(1/5*x^1-6/5*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(1/5*x^1-6/5*x^2-4*x^0) = 0

x^1

(-6/5)*x^2+(1/5)*x-4 = 0

(-6/5)*x^2+(1/5)*x-4 = 0

DELTA = (1/5)^2-(-4*4*(-6/5))

DELTA = -479/25

DELTA < 0

x in { } 

x belongs to the empty set

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