(1/5)-(8/5b)=1/b

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Solution for (1/5)-(8/5b)=1/b equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

1/5-((8/5)*b) = 1/b // - 1/b

1/5-((8/5)*b)-(1/b) = 0

(-8/5)*b-b^-1+1/5 = 0

1/5*b^0-8/5*b^1-1*b^-1 = 0

(1/5*b^1-8/5*b^2-1*b^0)/(b^1) = 0 // * b^2

b^1*(1/5*b^1-8/5*b^2-1*b^0) = 0

b^1

(-8/5)*b^2+(1/5)*b-1 = 0

(-8/5)*b^2+(1/5)*b-1 = 0

DELTA = (1/5)^2-(-1*4*(-8/5))

DELTA = -159/25

DELTA < 0

b in { } 

b belongs to the empty set

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