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(1/5)-3b=5
We move all terms to the left:
(1/5)-3b-(5)=0
determiningTheFunctionDomain -3b-5+(1/5)=0
We add all the numbers together, and all the variables
-3b-5+(+1/5)=0
We get rid of parentheses
-3b-5+1/5=0
We multiply all the terms by the denominator
-3b*5+1-5*5=0
We add all the numbers together, and all the variables
-3b*5-24=0
Wy multiply elements
-15b-24=0
We move all terms containing b to the left, all other terms to the right
-15b=24
b=24/-15
b=-1+3/5
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