(1/5)b+(2/3)-2=b-(2/5)

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Solution for (1/5)b+(2/3)-2=b-(2/5) equation: 



(1/5)b+(2/3)-2=b-(2/5)

We move all terms to the left:

(1/5)b+(2/3)-2-(b-(2/5))=0



Domain of the equation: 5)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+1/5)b-(b-(+2/5))-2+(+2/3)=0

We multiply parentheses

b^2-(b-(+2/5))-2+(+2/3)=0

We get rid of parentheses

b^2-(b-(+2/5))-2+2/3=0

We calculate fractions


b^2+(-(b-(+2*3)/()+()/()-2=0

We can not solve this equation

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