(1/5)x+3=2

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Solution for (1/5)x+3=2 equation: 



(1/5)x+3=2

We move all terms to the left:

(1/5)x+3-(2)=0



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/5)x+3-2=0

We add all the numbers together, and all the variables

(+1/5)x+1=0

We multiply parentheses

x^2+1=0

a = 1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·1·1
Δ = -4
Delta is less than zero, so there is no solution for the equation

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