(1/5)x-1/2=1/20(4x-5)-3/4

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Solution for (1/5)x-1/2=1/20(4x-5)-3/4 equation: 


x in (-oo:+oo)

(1/5)*x-(1/2) = (1/20)*(4*x-5)-(3/4) // - (1/20)*(4*x-5)-(3/4)

(1/5)*x-((1/20)*(4*x-5))-(1/2)+3/4 = 0

(-1/20)*(4*x-5)+(1/5)*x-1/2+3/4 = 0

x/5-1/20*(4*x-5)-1/2+3/4 = 0

(-1/20*2*4*5*(4*x-5))/(2*4*5)+(2*4*x)/(2*4*5)+(-1*4*5)/(2*4*5)+(2*3*5)/(2*4*5) = 0

2*4*x-1/20*2*4*5*(4*x-5)-1*4*5+2*3*5 = 0

10-20+30 = 0

30-10 = 0

20 = 0

20/(2*4*5) = 0

20/(2*4*5) = 0 // * 2*4*5

20 = 0

20 = 0

x belongs to the empty set

x belongs to the empty set

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