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(1/5)x-26=(1/2)x-29
We move all terms to the left:
(1/5)x-26-((1/2)x-29)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2)x-29)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/5)x-((+1/2)x-29)-26=0
We multiply parentheses
x^2-((+1/2)x-29)-26=0
We multiply all the terms by the denominator
x^2*2)x-29)-((-26*2)x-29)+1=0
We add all the numbers together, and all the variables
x^2*2)x-29)-((-52)x-29)+1=0
Wy multiply elements
2x^3-52)x-29)+1=0
We do not support expression: x^3
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