(1/5)y+(1/8)=(7/40)

Solution for (1/5)y+(1/8)=(7/40) equation:

(1/5)y+(1/8)=(7/40)

We move all terms to the left:

(1/5)y+(1/8)-((7/40))=0


Domain of the equation: 5)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/5)y+(+1/8)-((+7/40))=0

We multiply parentheses

y^2+(+1/8)-((+7/40))=0

We get rid of parentheses

y^2+1/8-((+7/40))=0

We calculate fractions


y^2+()/()+()/()=0

We add all the numbers together, and all the variables

y^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation