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(1/5x)+1/4=1/2(x+5)
We move all terms to the left:
(1/5x)+1/4-(1/2(x+5))=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2(x+5))!=0We add all the numbers together, and all the variables
x∈R
(+1/5x)-(1/2(x+5))+1/4=0
We get rid of parentheses
1/5x-(1/2(x+5))+1/4=0
We calculate fractions
(8xx/(40x^2x+(-(1*5x*4)/(40x^2x+20x^2/(40x^2x=0
We can not solve this equation
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