(1/5+4b)(1/13-5b)=0

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Solution for (1/5+4b)(1/13-5b)=0 equation: 


b in (-oo:+oo)

(4*b+1/5)*(1/13-(5*b)) = 0

(4*b+1/5)*(1/13-5*b) = 0

( 1/13-5*b )

1/13-5*b = 0 // - 1/13

-5*b = -1/13 // : -5

b = -1/13/(-5)

b = 1/65

( 4*b+1/5 )

4*b+1/5 = 0 // - 1/5

4*b = -1/5 // : 4

b = -1/5/4

b = -1/20

b in { 1/65, -1/20 }

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