(1/5-z)15=12

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Solution for (1/5-z)15=12 equation: 



(1/5-z)15=12

We move all terms to the left:

(1/5-z)15-(12)=0



Domain of the equation: 5-z)15!=0

We move all terms containing z to the left, all other terms to the right

-z)15!=-5

z!=-5/1

z!=-5

z∈R



We add all the numbers together, and all the variables

(-1z+1/5)15-12=0

We multiply parentheses

-15z-12+1/5*15=0

We multiply all the terms by the denominator


-15z*5*15+1-12*5*15=0

We add all the numbers together, and all the variables

-15z*5*15-899=0

Wy multiply elements

-1125z*1-899=0

Wy multiply elements

-1125z-899=0

We move all terms containing z to the left, all other terms to the right

-1125z=899

z=899/-1125

z=-899/1125

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