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(1/5x)-(13/30)=(3/2x)
We move all terms to the left:
(1/5x)-(13/30)-((3/2x))=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/5x)-((+3/2x))-(+13/30)=0
We get rid of parentheses
1/5x-((+3/2x))-13/30=0
We calculate fractions
(-((+3*5x*30)/300x^2+(-260x^2)/300x^2+60x/300x^2=0
We can not solve this equation
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