(1/6)(2x+32)=3x

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Solution for (1/6)(2x+32)=3x equation: 


x in (-oo:+oo)

(1/6)*(2*x+32) = 3*x // - 3*x

(1/6)*(2*x+32)-(3*x) = 0

(1/6)*(2*x+32)-3*x = 0

1/6*(2*x+32)-3*x = 0

1/6*(2*x+32)-3*x = 0

16/3-8/3*x = 0

16/3-8/3*x = 0

16/3-8/3*x = 0 // - 16/3

-8/3*x = -16/3 // : -8/3

x = -16/3/(-8/3)

x = 2

x = 2

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