(1/6)d+(2/3)=(1/4)(d-2)

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Solution for (1/6)d+(2/3)=(1/4)(d-2) equation: 


d in (-oo:+oo)

(1/6)*d+2/3 = (1/4)*(d-2) // - (1/4)*(d-2)

(1/6)*d-((1/4)*(d-2))+2/3 = 0

(-1/4)*(d-2)+(1/6)*d+2/3 = 0

d/6-1/4*(d-2)+2/3 = 0

(-1/4*3*6*(d-2))/(3*6)+(3*d)/(3*6)+(2*6)/(3*6) = 0

3*d-1/4*3*6*(d-2)+2*6 = 0

9-3/2*d+12 = 0

21-3/2*d = 0

(21-3/2*d)/(3*6) = 0

(21-3/2*d)/(3*6) = 0 // * 3*6

21-3/2*d = 0

21-3/2*d = 0 // - 21

-3/2*d = -21 // : -3/2

d = -21/(-3/2)

d = 14

d = 14

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