(1/6)d+2/3=1/4(d-2)

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Solution for (1/6)d+2/3=1/4(d-2) equation: 



(1/6)d+2/3=1/4(d-2)

We move all terms to the left:

(1/6)d+2/3-(1/4(d-2))=0



Domain of the equation: 6)d!=0

d!=0/1

d!=0

d∈R





Domain of the equation: 4(d-2))!=0

d∈R



We add all the numbers together, and all the variables

(+1/6)d-(1/4(d-2))+2/3=0

We multiply parentheses

d^2-(1/4(d-2))+2/3=0

We calculate fractions


d^2+()/12d+(8dd/12d=0

We multiply all the terms by the denominator


d^2*12d+(8dd+()=0



We calculate terms in parentheses: +(8dd+(), so:

8dd+(

We add all the numbers together, and all the variables

8dd

Back to the equation:

+(8dd)



Wy multiply elements

12d^3+8dd=0

We do not support edpression: d^3

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