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(1/6)d+2/3=1/4(d-2)
We move all terms to the left:
(1/6)d+2/3-(1/4(d-2))=0
Domain of the equation: 6)d!=0
d!=0/1
d!=0
d∈R
Domain of the equation: 4(d-2))!=0We add all the numbers together, and all the variables
d∈R
(+1/6)d-(1/4(d-2))+2/3=0
We multiply parentheses
d^2-(1/4(d-2))+2/3=0
We calculate fractions
d^2+()/12d+(8dd/12d=0
We multiply all the terms by the denominator
d^2*12d+(8dd+()=0
We calculate terms in parentheses: +(8dd+(), so:Wy multiply elements
8dd+(
We add all the numbers together, and all the variables
8dd
Back to the equation:
+(8dd)
12d^3+8dd=0
We do not support edpression: d^3
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