(1/6)m=1/9

Solution for (1/6)m=1/9 equation:

(1/6)m=1/9

We move all terms to the left:

(1/6)m-(1/9)=0


Domain of the equation: 6)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+1/6)m-(+1/9)=0

We multiply parentheses

m^2-(+1/9)=0

We get rid of parentheses

m^2-1/9=0

We multiply all the terms by the denominator


m^2*9-1=0

Wy multiply elements

9m^2-1=0

a = 9; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·9·(-1)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*9}=\frac{-6}{18}
=-1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*9}=\frac{6}{18}
=1/3
$