(1/6)p-(8/15)=(2/3)p+3

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Solution for (1/6)p-(8/15)=(2/3)p+3 equation: 



(1/6)p-(8/15)=(2/3)p+3

We move all terms to the left:

(1/6)p-(8/15)-((2/3)p+3)=0



Domain of the equation: 6)p!=0

p!=0/1

p!=0

p∈R





Domain of the equation: 3)p+3)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

(+1/6)p-((+2/3)p+3)-(+8/15)=0

We multiply parentheses

p^2-((+2/3)p+3)-(+8/15)=0

We get rid of parentheses

p^2-((+2/3)p+3)-8/15=0

We calculate fractions


p^2+()/3p+3)*15)+(-24p)/3p+3)*15)=0

We calculate fractions


p^2+(()*3p)/9p^2-24p)*3p)/9p^2+3*15)+(=0

We calculate fractions

We do not support eppression: p^4

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