(1/6)x+4=(1/3)(x-3)-1.5x

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Solution for (1/6)x+4=(1/3)(x-3)-1.5x equation: 



(1/6)x+4=(1/3)(x-3)-1.5x

We move all terms to the left:

(1/6)x+4-((1/3)(x-3)-1.5x)=0



Domain of the equation: 6)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)(x-3)-1.5x)!=0

x∈R



We add all the numbers together, and all the variables

(+1/6)x-((+1/3)(x-3)-1.5x)+4=0

We multiply parentheses

x^2-((+1/3)(x-3)-1.5x)+4=0

We multiply parentheses ..

x^2-((+x^2+1/3*-3)-1.5x)+4=0

We multiply all the terms by the denominator


x^2+x^2*3*-3)-1.5x)-((-3)-1.5x)+1+4*3*=0

Wy multiply elements

x^2+3x^3-3)-1.5x)-((-3)-1.5x)+1+4*3*=0

We do not support expression: x^3

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