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(1/6)x-x=25
We move all terms to the left:
(1/6)x-x-(25)=0
Domain of the equation: 6)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/6)x-x-25=0
We add all the numbers together, and all the variables
-1x+(+1/6)x-25=0
We multiply parentheses
x^2-1x-25=0
a = 1; b = -1; c = -25;
Δ = b2-4ac
Δ = -12-4·1·(-25)
Δ = 101
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{101}}{2*1}=\frac{1-\sqrt{101}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{101}}{2*1}=\frac{1+\sqrt{101}}{2} $
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