(1/6)y-(1/7)=(y/3)

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Solution for (1/6)y-(1/7)=(y/3) equation: 



(1/6)y-(1/7)=(y/3)

We move all terms to the left:

(1/6)y-(1/7)-((y/3))=0



Domain of the equation: 6)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/6)y-((+y/3))-(+1/7)=0

We multiply parentheses

y^2-((+y/3))-(+1/7)=0

We get rid of parentheses

y^2-((+y/3))-1/7=0

We calculate fractions


y^2+(-((+y*7)/()+()/()=0



We calculate terms in parentheses: +(-((+y*7)/()+()/(), so:

-((+y*7)/()+()/(

We can not solve this equation

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