(1/7)(6x-8)=((1+8)/14)

Solution for (1/7)(6x-8)=((1+8)/14) equation:

(1/7)(6x-8)=((1+8)/14)

We move all terms to the left:

(1/7)(6x-8)-(((1+8)/14))=0


Domain of the equation: 7)(6x-8)!=0

x∈R


We add all the numbers together, and all the variables

(+1/7)(6x-8)-((9/14))=0

We multiply parentheses ..

(+6x^2+1/7*-8)-((9/14))=0

We calculate fractions


6x^2/()+()/()=0

We add all the numbers together, and all the variables

6x^2/()+1=0

We multiply all the terms by the denominator


6x^2+1*()=0

We add all the numbers together, and all the variables

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$