(1/7)2x=(1/7)x+15

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Solution for (1/7)2x=(1/7)x+15 equation: 



(1/7)2x=(1/7)x+15

We move all terms to the left:

(1/7)2x-((1/7)x+15)=0



Domain of the equation: 7)2x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 7)x+15)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/7)2x-((+1/7)x+15)=0

We multiply parentheses

2x^2-((+1/7)x+15)=0

We multiply all the terms by the denominator


2x^2*7)x+15)-((+1=0

Wy multiply elements

14x^3+1=0

We do not support expression: x^3

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