(1/7)k-6=(3/7k)+4

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Solution for (1/7)k-6=(3/7k)+4 equation: 



(1/7)k-6=(3/7k)+4

We move all terms to the left:

(1/7)k-6-((3/7k)+4)=0



Domain of the equation: 7)k!=0

k!=0/1

k!=0

k∈R





Domain of the equation: 7k)+4)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+1/7)k-((+3/7k)+4)-6=0

We multiply parentheses

k^2-((+3/7k)+4)-6=0

We multiply all the terms by the denominator


k^2*7k)+4)-((-6*7k)+4)+3=0

Wy multiply elements

7k^3-42k=0

We do not support ekpression: k^3

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