(1/7)x+(1/9)x+(1/7)=(73/63)

Solution for (1/7)x+(1/9)x+(1/7)=(73/63) equation:

(1/7)x+(1/9)x+(1/7)=(73/63)

We move all terms to the left:

(1/7)x+(1/9)x+(1/7)-((73/63))=0


Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 9)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/7)x+(+1/9)x+(+1/7)-((+73/63))=0

We multiply parentheses

x^2+x^2+(+1/7)-((+73/63))=0

We get rid of parentheses

x^2+x^2+1/7-((+73/63))=0

We calculate fractions


x^2+x^2+()/()+()/()=0

We add all the numbers together, and all the variables

2x^2+2=0

a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation