(1/7x-3)+(1/7x+3)=180

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Solution for (1/7x-3)+(1/7x+3)=180 equation: 



(1/7x-3)+(1/7x+3)=180

We move all terms to the left:

(1/7x-3)+(1/7x+3)-(180)=0



Domain of the equation: 7x-3)!=0

x∈R





Domain of the equation: 7x+3)!=0

x∈R



We get rid of parentheses

1/7x+1/7x-3+3-180=0

We multiply all the terms by the denominator


-3*7x+3*7x-180*7x+1+1=0

We add all the numbers together, and all the variables

-3*7x+3*7x-180*7x+2=0

Wy multiply elements

-21x+21x-1260x+2=0

We add all the numbers together, and all the variables

-1260x+2=0

We move all terms containing x to the left, all other terms to the right

-1260x=-2

x=-2/-1260

x=1/630

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