(1/8)=(2m)+(1/m)

Solution for (1/8)=(2m)+(1/m) equation:

(1/8)=(2m)+(1/m)

We move all terms to the left:

(1/8)-((2m)+(1/m))=0


Domain of the equation: m))!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

-(2m+(+1/m))+(+1/8)=0

We get rid of parentheses

-(2m+(+1/m))+1/8=0

We calculate fractions


(-(2m+(+1*8)/m)*8)+m/m)*8)=0


We calculate terms in parentheses: +(-(2m+(+1*8)/m)*8), so:

-(2m+(+1*8)/m)*8

We add all the numbers together, and all the variables

-(2m+8/m)*8

We multiply parentheses

-16m-64m

We add all the numbers together, and all the variables

-80m

Back to the equation:

+(-80m)


We get rid of parentheses

-80m+m/m)*8)=0

We multiply all the terms by the denominator


-80m*m)*8)+m=0

Wy multiply elements

-640m^3=0

We do not support empression: m^3