(1/8)y+3=-9

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Solution for (1/8)y+3=-9 equation: 



(1/8)y+3=-9

We move all terms to the left:

(1/8)y+3-(-9)=0



Domain of the equation: 8)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/8)y+3-(-9)=0

We add all the numbers together, and all the variables

(+1/8)y+12=0

We multiply parentheses

y^2+12=0

a = 1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·1·12
Δ = -48
Delta is less than zero, so there is no solution for the equation

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