(1/9-3x)(1/5+2x)=0

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Solution for (1/9-3x)(1/5+2x)=0 equation: 


x in (-oo:+oo)

(1/9-(3*x))*(2*x+1/5) = 0

(1/9-3*x)*(2*x+1/5) = 0

( 1/9-3*x )

1/9-3*x = 0 // - 1/9

-3*x = -1/9 // : -3

x = -1/9/(-3)

x = 1/27

( 2*x+1/5 )

2*x+1/5 = 0 // - 1/5

2*x = -1/5 // : 2

x = -1/5/2

x = -1/10

x in { 1/27, -1/10 }

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