(1/X)+(1/X+11)=(21/11X+33)

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Solution for (1/X)+(1/X+11)=(21/11X+33) equation: 


D( X )

X = 0

X = 0

X = 0

X in (-oo:0) U (0:+oo)

1/X+1/X+11 = (21/11)*X+33 // - (21/11)*X+33

1/X-((21/11)*X)+1/X-33+11 = 0

(-21/11)*X+1/X+1/X-33+11 = 0

2*X^-1-21/11*X^1-22*X^0 = 0

(2*X^0-21/11*X^2-22*X^1)/(X^1) = 0 // * X^2

X^1*(2*X^0-21/11*X^2-22*X^1) = 0

X^1

(-21/11)*X^2-22*X+2 = 0

(-21/11)*X^2-22*X+2 = 0

DELTA = (-22)^2-(2*4*(-21/11))

DELTA = 5492/11

DELTA > 0

X = ((5492/11)^(1/2)+22)/(2*(-21/11)) or X = (22-(5492/11)^(1/2))/(2*(-21/11))

X = -11/42*((5492/11)^(1/2)+22) or X = -11/42*(22-(5492/11)^(1/2))

X in { -11/42*((5492/11)^(1/2)+22), -11/42*(22-(5492/11)^(1/2))} 

X in { -11/42*((5492/11)^(1/2)+22), -11/42*(22-(5492/11)^(1/2)) }

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