(1/a)+(1/b)=(1/x)

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Solution for (1/a)+(1/b)=(1/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/a+1/b = 1/x // - 1/x

1/a+1/b-(1/x) = 0

1/a+1/b-x^-1 = 0

-1*x^-1 = -(a^-1+b^-1) // : -1

x^-1 = a^-1+b^-1

-1 < 0

1/(x^1) = a^-1+b^-1 // * x^1

1 = x^1*(a^-1+b^-1) // : a^-1+b^-1

1/(a^-1+b^-1) = x^1

x = 1/(a^-1+b^-1)

x = 1/(a^-1+b^-1)

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