(1/b)=(-3)/(b+2)

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Solution for (1/b)=(-3)/(b+2) equation: 


D( b )

b+2 = 0

b = 0

b+2 = 0

b+2 = 0

b+2 = 0 // - 2

b = -2

b = 0

b = 0

b in (-oo:-2) U (-2:0) U (0:+oo)

1/b = -3/(b+2) // + -3/(b+2)

1/b-(-3/(b+2)) = 0

3*(b+2)^-1+1/b = 0

3/(b+2)+1/b = 0

(3*b)/(b*(b+2))+(1*(b+2))/(b*(b+2)) = 0

1*(b+2)+3*b = 0

4*b+2 = 0

(4*b+2)/(b*(b+2)) = 0

(4*b+2)/(b*(b+2)) = 0 // * b*(b+2)

4*b+2 = 0

4*b+2 = 0 // - 2

4*b = -2 // : 4

b = -2/4

b = -1/2

b = -1/2

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