(1/m)+(1/2m)=1/2

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Solution for (1/m)+(1/2m)=1/2 equation:


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

(1/2)*m+1/m = 1/2 // - 1/2

(1/2)*m+1/m-(1/2) = 0

(1/2)*m+1/m-1/2 = 0

1/2*m^1+1*m^-1-1/2*m^0 = 0

(1/2*m^2-1/2*m^1+1*m^0)/(m^1) = 0 // * m^2

m^1*(1/2*m^2-1/2*m^1+1*m^0) = 0

m^1

(1/2)*m^2+(-1/2)*m+1 = 0

(1/2)*m^2+(-1/2)*m+1 = 0

DELTA = (-1/2)^2-(1*4*(1/2))

DELTA = -7/4

DELTA < 0

m in { }

m belongs to the empty set

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