(1/m)=(m-2)/24

Solution for (1/m)=(m-2)/24 equation:

(1/m)=(m-2)/24

We move all terms to the left:

(1/m)-((m-2)/24)=0


Domain of the equation: m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(+1/m)-((m-2)/24)=0

We get rid of parentheses

1/m-((m-2)/24)=0

We calculate fractions


()/24m^2+(-((m-2)*m)/24m^2=0

We multiply all the terms by the denominator


(-((m-2)*m)+()=0


We calculate terms in parentheses: +(-((m-2)*m)+(), so:

-((m-2)*m)+(

We add all the numbers together, and all the variables

-((m-2)*m)


We calculate terms in parentheses: -((m-2)*m), so:

(m-2)*m

We multiply parentheses

m^2-2m

Back to the equation:

-(m^2-2m)


We get rid of parentheses

-m^2+2m

We add all the numbers together, and all the variables

-1m^2+2m

Back to the equation:

+(-1m^2+2m)


We get rid of parentheses

-1m^2+2m=0

a = -1; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-1)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-1}=\frac{-4}{-2}
=+2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-1}=\frac{0}{-2}
=0
$