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(1/n)+(2/(n+1))=2
We move all terms to the left:
(1/n)+(2/(n+1))-(2)=0
Domain of the equation: n)!=0
n!=0/1
n!=0
n∈R
Domain of the equation: (n+1))!=0We add all the numbers together, and all the variables
n∈R
(+1/n)+(2/(n+1))-2=0
We get rid of parentheses
1/n+(2/(n+1))-2=0
We calculate fractions
(1*(n+1)))/2n^2+((2*n)/2n^2-2=0
We can not solve this equation
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