(1/n)=(1/5n)-(n-1/5n)

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Solution for (1/n)=(1/5n)-(n-1/5n) equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

1/n = (1/5)*n-n+(1/5)*n // - (1/5)*n-n+(1/5)*n

n-((1/5)*n)-((1/5)*n)+1/n = 0

(-1/5)*n+n+(-1/5)*n+1/n = 0

3/5*n^1+1*n^-1 = 0

(3/5*n^2+1*n^0)/(n^1) = 0 // * n^2

n^1*(3/5*n^2+1*n^0) = 0

n^1

(3/5)*n^2+1 = 0

(3/5)*n^2+1 = 0

DELTA = 0^2-(1*4*(3/5))

DELTA = -12/5

DELTA < 0

n in { } 

n belongs to the empty set

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