(1/p)+(1/(p-1))=-2

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Solution for (1/p)+(1/(p-1))=-2 equation: 


D( p )

p = 0

p-1 = 0

p = 0

p = 0

p-1 = 0

p-1 = 0

p-1 = 0 // + 1

p = 1

p in (-oo:0) U (0:1) U (1:+oo)

1/(p-1)+1/p = -2 // + 2

1/(p-1)+1/p+2 = 0

(1*p)/(p*(p-1))+(1*(p-1))/(p*(p-1))+(2*p*(p-1))/(p*(p-1)) = 0

1*(p-1)+2*p*(p-1)+1*p = 0

2*p^2+2*p-2*p-1 = 0

2*p^2-1 = 0

(2*p^2-1)/(p*(p-1)) = 0

(2*p^2-1)/(p*(p-1)) = 0 // * p*(p-1)

2*p^2-1 = 0

2*p^2 = 1 // : 2

p^2 = 1/2

p^2 = 1/2 // ^ 1/2

abs(p) = (1/2)^(1/2)

p = (1/2)^(1/2) or p = -(1/2)^(1/2)

p in { (1/2)^(1/2), -(1/2)^(1/2) }

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