(1/p)=(p+4)/(2p)((1)/(2p))

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Solution for (1/p)=(p+4)/(2p)((1)/(2p)) equation: 


D( p )

p = 0

2*p = 0

p = 0

p = 0

2*p = 0

2*p = 0

2*p = 0 // : 2

p = 0

p in (-oo:0) U (0:+oo)

1/p = (1/(2*p))*((p+4)/(2*p)) // - (1/(2*p))*((p+4)/(2*p))

1/p-((1/(2*p))*((p+4)/(2*p))) = 0

(-1/4)*p^-2*(p+4)+1/p = 0

1/p-1/4*p^-2*(p+4) = 0

(-1/4*p^-2*p*(p+4))/p+1/p = 0

1-1/4*p^-2*p*(p+4) = 0

3/4-p^-1 = 0

(3/4-p^-1)/p = 0

(3/4-p^-1)/p = 0 // * p

3/4-p^-1 = 0

-1*p^-1 = -3/4 // : -1

p^-1 = 3/4

-1 < 0

1/(p^1) = 3/4 // * p^1

1 = 3/4*p^1 // : 3/4

4/3 = p^1

p = 4/3

p = 4/3

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