(1/w+2)+(7/5w)

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Solution for (1/w+2)+(7/5w) equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

(7/5)*w+1/w+2 = 0

7/5*w^1+1*w^-1+2*w^0 = 0

(7/5*w^2+2*w^1+1*w^0)/(w^1) = 0 // * w^2

w^1*(7/5*w^2+2*w^1+1*w^0) = 0

w^1

(7/5)*w^2+2*w+1 = 0

(7/5)*w^2+2*w+1 = 0

DELTA = 2^2-(1*4*(7/5))

DELTA = -8/5

DELTA < 0

w in { } 

w belongs to the empty set

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