(1/w-1)-(3/4w-4)=1/4w-4

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Solution for (1/w-1)-(3/4w-4)=1/4w-4 equation:


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((3/4)*w)-1+4 = (1/4)*w-4 // - (1/4)*w-4

1/w-((3/4)*w)-((1/4)*w)-1+4+4 = 0

(-3/4)*w+(-1/4)*w+1/w-1+4+4 = 0

1*w^-1-1*w^1+7*w^0 = 0

(7*w^1-1*w^2+1*w^0)/(w^1) = 0 // * w^2

w^1*(7*w^1-1*w^2+1*w^0) = 0

w^1

7*w-w^2+1 = 0

7*w-w^2+1 = 0

DELTA = 7^2-(-1*1*4)

DELTA = 53

DELTA > 0

w = (53^(1/2)-7)/(-1*2) or w = (-53^(1/2)-7)/(-1*2)

w = (53^(1/2)-7)/(-2) or w = (53^(1/2)+7)/2

w in { (53^(1/2)-7)/(-2), (53^(1/2)+7)/2}

w in { (53^(1/2)-7)/(-2), (53^(1/2)+7)/2 }

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