(1/w-2)-(1/w-2)=1/3w-6

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Solution for (1/w-2)-(1/w-2)=1/3w-6 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-(1/w)-2+2 = (1/3)*w-6 // - (1/3)*w-6

1/w-((1/3)*w)-(1/w)-2+2+6 = 0

(-1/3)*w+1/w-w^-1-2+2+6 = 0

6-1/3*w = 0 // - 6

-1/3*w = -6 // : -1/3

w = -6/(-1/3)

w = 18

w = 18

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