(1/w-3)-(1/5w-15)=4/5w-15

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Solution for (1/w-3)-(1/5w-15)=4/5w-15 equation:


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

1/w-((1/5)*w)-3+15 = (4/5)*w-15 // - (4/5)*w-15

1/w-((1/5)*w)-((4/5)*w)-3+15+15 = 0

(-1/5)*w+(-4/5)*w+1/w-3+15+15 = 0

1*w^-1-1*w^1+27*w^0 = 0

(27*w^1-1*w^2+1*w^0)/(w^1) = 0 // * w^2

w^1*(27*w^1-1*w^2+1*w^0) = 0

w^1

27*w-w^2+1 = 0

27*w-w^2+1 = 0

DELTA = 27^2-(-1*1*4)

DELTA = 733

DELTA > 0

w = (733^(1/2)-27)/(-1*2) or w = (-733^(1/2)-27)/(-1*2)

w = (733^(1/2)-27)/(-2) or w = (733^(1/2)+27)/2

w in { (733^(1/2)-27)/(-2), (733^(1/2)+27)/2}

w in { (733^(1/2)-27)/(-2), (733^(1/2)+27)/2 }

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