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(1/x)+(1/(x+3))=1/2
We move all terms to the left:
(1/x)+(1/(x+3))-(1/2)=0
Domain of the equation: x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: (x+3))!=0We add all the numbers together, and all the variables
x∈R
(+1/x)+(1/(x+3))-(+1/2)=0
We get rid of parentheses
1/x+(1/(x+3))-1/2=0
We calculate fractions
((1*x*2)/8x^2+(-1x^2*()/8x^2+2x/8x^2=0
We can not solve this equation
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