(1/x)+(1/2x)=(1/13)

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Solution for (1/x)+(1/2x)=(1/13) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/2)*x+1/x = 1/13 // - 1/13

(1/2)*x+1/x-(1/13) = 0

(1/2)*x+1/x-1/13 = 0

1/2*x^1+1*x^-1-1/13*x^0 = 0

(1/2*x^2-1/13*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^2-1/13*x^1+1*x^0) = 0

x^1

(1/2)*x^2+(-1/13)*x+1 = 0

(1/2)*x^2+(-1/13)*x+1 = 0

DELTA = (-1/13)^2-(1*4*(1/2))

DELTA = -337/169

DELTA < 0

x in { } 

x belongs to the empty set

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