(1/x)+(1/5x)=(1/15)

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Solution for (1/x)+(1/5x)=(1/15) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(1/5)*x+1/x = 1/15 // - 1/15

(1/5)*x+1/x-(1/15) = 0

(1/5)*x+1/x-1/15 = 0

1/5*x^1+1*x^-1-1/15*x^0 = 0

(1/5*x^2-1/15*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1/5*x^2-1/15*x^1+1*x^0) = 0

x^1

(1/5)*x^2+(-1/15)*x+1 = 0

(1/5)*x^2+(-1/15)*x+1 = 0

DELTA = (-1/15)^2-(1*4*(1/5))

DELTA = -179/225

DELTA < 0

x in { } 

x belongs to the empty set

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