(1/x)+(1/x+2)=(1/5)

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Solution for (1/x)+(1/x+2)=(1/5) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x+2 = 1/5 // - 1/5

1/x+1/x-(1/5)+2 = 0

1/x+1/x-1/5+2 = 0

2*x^-1 = -9/5 // : 2

x^-1 = -9/10

-1 < 0

1/(x^1) = -9/10 // * x^1

1 = -9/10*x^1 // : -9/10

-10/9 = x^1

x = -10/9

x = -10/9

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